How to add guid regex in angular ui-router state

Answer 1

You can define your own type of parameter.

var GUID_REGEXP = /^[a-f\d]{8}-([a-f\d]{4}-){3}[a-f\d]{12}$/i;
$urlMatcherFactoryProvider.type('guid', {
  encode: angular.identity,
  decode: angular.identity,
  is: function(item) {
     return GUID_REGEXP.test(item);
  }
});

Here is a showcase on plunker with this solution

Then specify this type in url route expression:

.state('mystate', {
  url: '/{id?guid}',
  templateUrl: '/views/partial.html'
});

You can read more on that page in docs

Answer 2

After much trial and error, I came up with:

$urlMatcherFactoryProvider.type('guid', {
    encode: angular.identity,
    decode: angular.identity,
    equals: function(a, b) { return a.toUpperCase() === b.toUpperCase(); },
    is: function(val) {
        // Local to avoid any lastIndex issues
        var GUID_REGEXP = /^[a-f\d]{8}-(?:[a-f\d]{4}-){3}[a-f\d]{12}$/i;
        return GUID_REGEXP.test(val);
    },
    // No anchors or flags with pattern
    pattern: /[a-fA-F\d]{8}-(?:[a-fA-F\d]{4}-){3}[a-fA-F\d]{12}/
});

This is based on @just-boris's answer. One key difference is pattern. Without this it appears that invalid GUIDs will not trigger $urlRouterProvider.otherwise().

Answer 3

There is a working plunker

We can just provide regexp in the url definition:

url: "/{id:(?:[a-fA-F0-9]{8}(?:-[a-fA-F0-9]{4}){3}-[a-fA-F0-9]{12})}",

Read more about our options for url defintion:

http://angular-ui.github.io/ui-router/site/#/api/ui.router.util.type:UrlMatcher

small snippet:

'{' name ':' regexp|type '}' - curly placeholder with regexp or type name. Should the regexp itself contain curly braces, they must be in matched pairs or escaped with a backslash.