How to Keep the selected value of the select box after Form POST or GET

Question

Im trying to implement the search feature in my website.

when the search keyword is entered in the textbox, and the category combo is selected, the form will be Pos

Answer 1

$countries_uid = $_POST['countries_uid'];
                while($row = mysql_fetch_array($result)){
                  $uid = $row['uid'];
                  $country = $row['country_name'];
                  $isSelected = null;
                    if(!empty($countries_uid)){
                    foreach($countries_uid as $country_uid){//cycle through country_uid
                       if($row['uid'] == $country_uid){
                        $isSelected = 'selected="selected"'; // if the option submited in form is as same as this row we add the selected
                       }
                    }
                   }else {
                    $isSelected = ''; // else we remove any tag
                  }
                  echo "<option value='".$uid."'".$isSelected.">".$country."</option>";
                }

this is my solutions of multiple select dropdown box after modifying Mihai Iorga codes

Answer 2

Easy solution: If select box values fetched from DB then to keep selected value after form submit OR form POST

 <select name="country" id="country">
        <?php $countries = $wpdb->get_results( 'SELECT * FROM countries' ); ?>
        <option value="">
        <?php if(isset($_POST['country'])){echo htmlentities($_POST['country']); } else { echo "Select Country *"; }?>
        </option>
        <?php foreach($countries as $country){  ?>
        <option <?php echo ($_POST['country'] == $country->country_name ? 'selected="selected"':''); ?> value="<?php echo $country->country_name; ?>"><?php echo $country->country_name; ?>
        </option>
        <?php } ?>
      </select>

Answer 3

Assuming that by "combo" you mean "A regular select element rendering as a drop down menu or list box" and not "A combobox that is a combination of a drop down menu and free text input":

When outputting the <option> elements, check the value against the submitted data in $_POST / $_GET and output selected (in HTML) or selected="selected" (in XHTML) as an attribute of the option element.

Answer 4

<?php
$example = $_POST["friend"];
?>
<form method="POST">
<select name="friend">
   <option value="tom" <?php if (isset($example) && $example=="tom") echo ' selected';?>>Thomas Finnegan</option>
   <option value="anna" <?php if (isset($example) && $example=="anna") echo ' selected';?>>Anna Karenina</option>
</select>
<br><br>
<input type="submit">
</form>

This solved my problem.

Answer 5

After trying al this "solves" nothing work. Did some research on w3school before and remember there was explanation of keeping values about radio. But it also works for Select option. See here an example. Just try it out and play with it.

<?php
$example = $_POST["example"];
?>
<form method="post">        
<select name="example">
    <option <?php if (isset($example) && $example=="a") echo "selected";?>>a</option>
    <option <?php if (isset($example) && $example=="b") echo "selected";?>>b</option>
    <option <?php if (isset($example) && $example=="c") echo "selected";?>>c</option>
</select>
<input type="submit" name="submit" value="submit" />
</form>

Answer 6

Here is the JQuery way I am using.

<select name="name" id="name">
  <option value="a">a</option>
  <option value="b">b</option>
</select>

<script type="text/javascript">
   $("#name").val("<?php echo $_POST['name'];?>");
</script>

But this is only if you have jquery included in your webpage. Regards