how to put a string into an integer array c++

Question

I have a string that contains what ever the user has input

string userstr = \"\";
cout << \"Please enter a string \";
getline (cin, userstr);
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Answer 1

You can access each element in your string using the [] operator, which will return a reference to a char. You can then deduct the int value for char '0' and you will get the correct int representation.

for(int i=0;i<userstr.length();i++){
    myarray[i] = userstr[i] - '0';
}

Answer 2

Here is one way to do it

for(int i=0;i<userstr.length();i++){
    myarray[i] = userstr[i];
}

Answer 3

You can just simply use isstringstream to convert the string to int as follows

istringstream istringName(intString);
istringName >> real_int_val;

now it has magically become a int containing all numbers from string However I do not see why you would not cin it as a int in the first place??

Answer 4

int* myarray = new int[ userstr.size() ];

std::copy( usestr.begin(), userstr.end(), myarray ); 

The terminating zero was not appended to the array. If you need it you should allocate the array having one more element and place the terminating zero yourself.