How to conduct arithmetic operations in JQuery?

Question

var price     = $(\'#addprice\').val();
var pass      = $(\'#pass\').val();
var total     = $(\'#totalprice\').attr(\'value\')
var left      = $(\'#leftquota\').attr         


        

Answer 1

you can use parseFloat for this case. it will return float value

example of usage:

var tprice = parseFloat(total) + parseFloat(price);

Answer 2

Have you tried parseFloat()?

documentation

Answer 3

use parseFloat, parseInt, or just place a + before string, if you sure it contains a number:

var text = "123.456";
var number = +text; // now 'number' is Number, and not String

Also something tells me that this should work faster than parseInt or parseFloat.

Another way to use Number object:

var text = "123.456";
var number = Number(text);

But this is the slowest way.

More info: http://www.jibbering.com/faq/faq_notes/type_convert.html#tcNumber

Answer 4

Another option is to extend jQuery to be able to read numbers directly from form elements

jQuery.fn.numVal = function() {
    return parseFloat(this.val()) || 0;
}

   ....

  var price=$('#addprice').numVal();
  var pass=$('#pass').numVal()

Answer 5

i was looking for a solution too , and i saw a lot of questions here that doesn't work (even this one) in case someone wondering like me , here is my working solutiuon :

$("#apport").keyup( 
function(){
var apport = parseFloat($("#apport").val());
var montant = parseFloat($("#montant-financer").val());
var moinmontant = parseFloat(montant) - parseFloat(apport);     
$("#montant-financer").val(moinmontant);    
}
);

All the id's selector are input