fgets adds \0 or \n at the end of the input?

Question

I\'ve some doubts about fgets. From what I know, it adds \"\\n\" at the end of the string, and not \"\\0\". So if I write this code:

fgets(buff,2,stdin);
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Answer 1

char * fgets ( char * str, int num, FILE * stream );

Reads characters from input stream and stores them as a C string into str until (num-1) characters have been read or either a newline or the end-of-file is reached, whichever happens first.

A newline character makes fgets stop reading, but it is considered a valid character by the function and included in the string copied to str.

A terminating null character ('\0') is automatically appended after the characters copied to str.

Answer 2

According to man page it clearly given :

 char *fgets(char *s, int size, FILE *stream);

fgets() reads in at most one less than size characters from stream and stores them into the buffer pointed to by s. Reading stops after an EOF or a newline. If a newline is read, it is stored into the buffer. A '\0' is stored after the last character in the buffer.

Answer 3

It must terminate the string, so yes it will always add '\0' at the end. However, fgets might not always add the newline, if it doesn't fit. I recommend this reference page for fgets.