Is it possible to send two lat long points to google to calculate the distance between the two?
Yes google can do this
google api docs
here's a piece of java script that get's the distance in km's for two points
function initialize() { if (GBrowserIsCompatible()) { map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(52.6345701, -1.1294433), 13); map.addControl(new GLargeMapControl()); map.addControl(new GMapTypeControl()); geocoder = new GClientGeocoder(); // NR14 7PZ var loc1 = new GLatLng(52.5773139, 1.3712427); // NR32 1TB var loc2 = new GLatLng(52.4788314, 1.7577444); alert(loc2.distanceFrom(loc1) / 1000); } }
No, but you can use Vincenty's formula, which models the shape of the Earth. It's available in Javascript here.
A quite easy to parse web page is (e.g.): http://boulter.com/gps/distance/?from=51.5329855+-0.1303506&to=40.757584+-73.985642&units=m
For people who only want a quick measure of distance, check out this gadget. However, it only uses the great circle calculation.
As Rob notes, Google have added it, but they still only use the great circle formula, which can be inaccurate by 1/300.
What you're after is the Haversine formula. You don't need Google Maps to do this, you can work it out separately. There's a script to do this (in JavaScript) here.
Its been many years since I did this but you could use the Great Circle Distance
If you just want to get the distance as a number, try something like this.
function InitDistances() {
var startLocation = new GLatLng(startLat, startLon);
var endLocation = new GLatLng(endLat, endLon);
var dist = startLocation .distanceFrom(endLocation);
// Convert distance to miles with two decimal points precision
return (dist / 1609.344).toFixed(2);
}
And the distance cal in c#:
// this returns the distance in miles. for km multiply result: * 1.609344
public static double CalculateDistance(double lat1, double lon1, double lat2, double lon2)
{
double t = lon1 - lon2;
double distance = Math.Sin(Degree2Radius(lat1)) * Math.Sin(Degree2Radius(lat2)) + Math.Cos(Degree2Radius(lat1)) * Math.Cos(Degree2Radius(lat2)) * Math.Cos(Degree2Radius(t));
distance = Math.Acos(distance);
distance = Radius2Degree(distance);
distance = distance * 60 * 1.1515;
return distance;
}
private static double Degree2Radius(double deg)
{
return (deg * Math.PI / 180.0);
}
private static double Radius2Degree(double rad)
{
return rad / Math.PI * 180.0;
}