Sorting strings by a substring in Python [duplicate]

Answer 1

def sort_csv(lines=[], delim=',', position=1):
    '''
    Returns a sorted list based on "column" from csv-type data.
    '''
    return sorted(lines, key=lambda x: x.split(delim)[int(position) - 1])


test_data = [
        'part1/foo/part1/partX',
        'part3/bar/part5/partX',
        'part4/fuz/partA/partX',
        'part2/buz/part3/partX',
        ]
# Sort by third element
pprint(sort_csv(test_data, '/', 3))
#['part1/foo/part1/partX',
# 'part2/buz/part3/partX',
# 'part3/bar/part5/partX',
# 'part4/fuz/partA/partX']

test_data = [
        'abc 12 34 3333',
        'bar 53 29 AAAA',
        'def 21 43 2222',
        'foo 53 29 5555',
        'fgh 21 43 1111',
]
# Sort by last element
pprint(sort_csv(test_data, ' ', 0))
#['fgh 21 43 1111',
# 'def 21 43 2222',
# 'abc 12 34 3333',
# 'foo 53 29 5555',
# 'bar 53 29 AAAA']

Answer 2

my_list = ['abc 12 34 3333',
           'def 21 43 2222',
           'fgh 21 43 1111']

my_list.sort(key=lambda x:int(x.split()[-1]))

my_list is now: ['fgh 21 43 1111', 'def 21 43 2222', 'abc 12 34 3333']

Answer 3

Like that:

sorted(your_list, lambda x: int(x.split()[-1]))