[removed] Function that retries with setTimeout

Question

I have a function downloadItem that may fail for network reasons, I want to be able to retry it a few times before actually rejecting that item. The retries nee

Answer 1

There is no need to create new promises to handle this. Assuming downloadItem is synchronous and returns a promise, simply return the result of calling it, along with a catch to call downloadItemWithRetryAndTimeout recursively.

function wait(n) { return new Promise(resolve => setTimeout(resolve, n)); }

function downloadItemWithRetryAndTimeout(url, retry) {
  if (retry < 0) return Promise.reject();

  return downloadItem(url) . 
    catch(() => wait(1000) . 
      then(() => downloadItemWithRetryAndTimeout(url, retry - 1)
  );
}

Some might find the following slightly cleaner:

function downloadItemWithRetryAndTimeout(url, retry) {
  return function download() {
    return --retry < 0 ? Promise.reject() :
      downloadItem(url) . catch(() => wait(1000) . then(download));
  }();
}

Answer 2

function downloadItemWithRetryAndTimeout(url, retry) {
    return new Promise(function(resolve, reject) {
        var tryDownload = function(attempts) {
            try {
                downloadItem(url);
                resolve();
            } catch (e) {
                if (attempts == 0)  {
                    reject(e);
                } else {
                    setTimeout(function() {
                        tryDownload(attempts - 1);
                    }, 1000);
                }
            }
        };
        tryDownload(retry);
    });
}

Answer 3

I've got two ideas:

Move the promise out side of the iterated function downloadItemWithRetryAndTimeout - now resolve() will available to all iterations:

function downloadWrapper(url, retry) {
    return new Promise(function (resolve, reject) {
        function downloadItemWithRetryAndTimeout(url, retry, failedReason) {

            try {
                if (retry < 0 && failedReason != null)
                    reject(failedReason);

                downloadItem(url);
                resolve();
            } catch (e) {
                setTimeout(function () {
                    downloadItemWithRetryAndTimeout(url, retry - 1, e);
                }, 1000);
            }

        }

        downloadItemWithRetryAndTimeout(url, retry, null);
    });
}

This solution works, but it's an anti pattern as it breaks the promise chain: As each iteration returns a promise, just resolve the promise, and use .then to resolve the previous promise, and so on:

function downloadItemWithRetryAndTimeout(url, retry, failedReason) {
    return new Promise(function (resolve, reject) {
        try {
            if (retry < 0 && failedReason != null)
                reject(failedReason);

            downloadItem(url);
            resolve();
        } catch (e) {
            setTimeout(function () {
                downloadItemWithRetryAndTimeout(url, retry - 1, e).then(function () {
                    resolve();
                });
            }, 1000);
        }
    });
}

Answer 4

@BenjaminGruenbaum comment on @user663031 is fantastic but there's a slight error because this:

const delayError = (fn, ms) => fn().catch(e => delay(ms).then(y => Promise.reject(e)))

should actually be:

const delayError = (fn, ms) => () => fn().catch(e => delay(ms).then(y => Promise.reject(e)))

so it will return a function, not a promise. It's a tricky error that's hard to solve so I'm posting on here in case anyone needs it. Here's the whole thing:

const retry = (fn, retries = 3) => fn().catch(e => retries <= 0 ? Promise.reject(e) : retry(fn, retries - 1))
const delay = ms => new Promise(resolve => setTimeout(resolve, ms))
const delayError = (fn, ms) => () => fn().catch(e => delay(ms).then(y => Promise.reject(e)))
retry(delayError(download, 1000))