I am trying to click on the first result on the google result. Here is my code where I am entering chennai craiglist which is read from csv file. So I am sure the first lin
The xpath
you have chosen is 'ok' but probably not the best.
result = driver.find_elements_by_xpath("//ol[@id="rso"]/li")[0] //make a list of results and get the first one
result.find_element_by_xpath("./div/h3/a").click() //click its href
I've been using driver.find_element_by_tag_name("cite").click()
in python3 which has worked for me. However if you just want the link to the top search result it would be faster to use the requests and BeautifulSoup libraries as shown below
#!/usr/bin/env python3
import requests
from bs4 import BeautifulSoup
url = 'http://www.google.com/search?q=something'
page = requests.get(url)
soup = BeautifulSoup(page.text, "html.parser")
print(soup.find('cite').text)
This works great with google results.
results = driver.find_elements_by_xpath('//div[@class="r"]/a/h3') # finds webresults
results[0].click(). # clicks the first one