Spring Boot, Hibernate Search properties

Question

How to provide Hibernate Search parameters when using Spring Boot?

...
spring.datasource.driverClassName=org.postgresql.Driver

hibernate.search.jmx_enabled=         


        

Answer 1

Got it working.

Put another property file named "hibernate.properties" inside src/main/resources with below content.

hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index

Answer 2

You can put them in the application.properties file if you put "spring.jpa.properties." in front of the property names.

Example:

spring.jpa.properties.hibernate.search.jmx_enabled=true
spring.jpa.properties.hibernate.search.default.directory_provider=filesystem
spring.jpa.properties.hibernate.search.generate_statistics=true
spring.jpa.properties.hibernate.search.lucene_version=LUCENE_CURRENT
spring.jpa.properties.hibernate.search.default.indexBase=/mypath-to-index

Spring will take any properties under spring.jpa.properties.* and pass them along (with the prefix stripped) once the EntityManagerFactory is created.