Regex nested parenthesis in python

Question

I have something like this:

Othername California (2000) (T) (S) (ok) {state (#2.1)}

Is there a regex code to obtain:

Other         


        

Answer 1

Despite what I have said in the comments. I've found a way around:

(?(?=\([^()\w]*[\w.]+[^()\w]*\))\([^()\w]*([\w.]+)[^()\w]*\)|.)(?=[^{]*\})|(?<!\()(\b\w+\b)(?!\()|ok

Explanation:

(?                                  # If
(?=\([^()\w]*[\w.]+[^()\w]*\))      # There is (anything except [()\w] zero or more times, followed by [\w.] one or more times, followed by anything except [()\w] zero or more times)
\([^()\w]*([\w.]+)[^()\w]*\)        # Then match it, and put [\w.] in a group
|                                   # else
.                                   # advance with one character
)                                   # End if
(?=[^{]*\})                         # Look ahead if there is anything except { zero or more times followed by }

|                                   # Or
(?<!\()(\b\w+\b)(?!\()              # Match a word not enclosed between parenthesis
|                                   # Or
ok                                  # Match ok

Online demo

Answer 2

other case is:

^(\w+\s?\w+)\s?\(\d{1,}\)\s?\(\w+\)\s?\(\w+\)\s?\((\w+)\)\s?.*#(\d.\d)

Answer 3

Try this one:

import re

thestr = 'Othername California (2000) (T) (S) (ok) {state (#2.1)}'

regex = r'''
    ([^(]*)             # match anything but a (
    \                   # a space
    (?:                 # non capturing parentheses
        \([^(]*\)       # parentheses
        \               # a space
    ){3}                # three times
    \(([^(]*)\)         # capture fourth parentheses contents
    \                   # a space
    {                   # opening {
        [^}]*           # anything but }
        \(\#            # opening ( followed by #
            ([^)]*)     # match anything but )
        \)              # closing )
    }                   # closing }
'''

match = re.match(regex, thestr, re.X)

print match.groups()

Output:

('Othername California', 'ok', '2.1')

And here's the compressed version:

import re

thestr = 'Othername California (2000) (T) (S) (ok) {state (#2.1)}'
regex = r'([^(]*) (?:\([^(]*\) ){3}\(([^(]*)\) {[^}]*\(\#([^)]*)\)}'
match = re.match(regex, thestr)

print match.groups()

Answer 4

Regex

(.+)\s+\(\d+\).+?(?:\(([^)]{2,})\)\s+(?={))?\{.+\(#(\d+\.\d+)\)\}

Text used for test

Name1 Name2 Name3 (2000) {Education (#3.2)}
Name1 Name2 Name3 (2000) (ok) {edu (#1.1)}
Name1 Name2 (2002) {edu (#1.1)}
Name1 Name2 Name3 (2000) (V) {variation (#4.12)}
Othername California (2000) (T) (S) (ok) {state (#2.1)}

Test

>>> regex = re.compile("(.+)\s+\(\d+\).+?(?:\(([^)]{2,})\)\s+(?={))?\{.+\(#(\d+\.\d+)\)\}")
>>> r = regex.search(string)
>>> r
<_sre.SRE_Match object at 0x54e2105f36c16a48>
>>> regex.match(string)
<_sre.SRE_Match object at 0x54e2105f36c169e8>

# Run findall
>>> regex.findall(string)
[
   (u'Name1 Name2 Name3'   , u''  , u'3.2'),
   (u'Name1 Name2 Name3'   , u'ok', u'1.1'),
   (u'Name1 Name2'         , u''  , u'1.1'),
   (u'Name1 Name2 Name3'   , u''  , u'4.12'),
   (u'Othername California', u'ok', u'2.1')
]