Substitution with sed + bash function

Question

my question seems to be general, but i can\'t find any answers.

In sed command, how can you replace the substitution pattern by a value returned by a simple bash fun

Answer 1

Bash function inside sed (maybe for other purposes):

multi_stdin(){ #Makes function accepet variable or stdin (via pipe)
    [[ -n "$1" ]] && echo "$*" || cat -
}

sans_accent(){ 
    multi_stdin "$@" | sed '
        y/àáâãäåèéêëìíîïòóôõöùúûü/aaaaaaeeeeiiiiooooouuuu/
        y/ÀÁÂÃÄÅÈÉÊËÌÍÎÏÒÓÔÕÖÙÚÛÜ/AAAAAAEEEEIIIIOOOOOUUUU/
        y/çÇñÑߢÐð£Øø§µÝý¥¹²³ªº/cCnNBcDdLOoSuYyY123ao/
    '
}

eval $(echo "Rogério Madureira" | sed -n 's#.*#echo & | sans_accent#p')

or

eval $(echo "Rogério Madureira" | sed -n 's#.*#sans_accent &#p')

Rogerio

And if you need to keep the output into a variable:

VAR=$( eval $(echo "Rogério Madureira" | sed -n 's#.*#echo & | desacentua#p') )
echo "$VAR"