Apply borders to all cells in a range with openpyxl

Question

I have a script that takes a pandas dataframe and chops it up into several hundred chunks and saves each chunk as a separate excel file. Each chunk will have the same number

Answer 1

@user698585 your approach seems nice but it doesn't work anymore as the present version of the openpyxl change the implementation. So this should be updated into e.g.

    ws.cell(row=1, column=1).style.border.top.border_style = borders.BORDER_MEDIUM

but it results with an error that changing the style is not allowed. As a workaround I just defined a dedicated styles, but they are just a duplication of the present styles plus border definition - not so good solution as works only if you know what style has the cell under the change.

    border_style = Style(font=Font(name='Console', size=10, bold=False,
                         color=Color(openpyxl.styles.colors.BLACK)),
                         fill=PatternFill(patternType='solid', fgColor=Color(rgb='00C5D9F1')),
                         border=Border(bottom=Side(border_style='medium', color=Color(rgb='FF000000'))))

Answer 2

Had the same issue but couldn't find anything that fixes this problem for 2019 because of depreciation. I have something that works below.. could be better but works for all intends and purposes.

def set_border(ws, cell_range):
    rows = ws[cell_range]
    for row in rows:
        if row == rows[0][0] or row == rows[0][-1] or row == rows[-1][0] or row == rows[-1][-1]:
            pass
        else:
            row[0].border = Border(left=Side(style='thin'))
            row[-1].border = Border(right=Side(style='thin'))
        for c in rows[0]:
            c.border = Border(top=Side(style='thin'))
        for c in rows[-1]:
            c.border = Border(bottom=Side(style='thin'))
    rows[0][0].border = Border(left=Side(style='thin'), top=Side(style='thin'))
    rows[0][-1].border = Border(right=Side(style='thin'), top=Side(style='thin'))
    rows[-1][0].border = Border(left=Side(style='thin'), bottom=Side(style='thin'))
    rows[-1][-1].border = Border(right=Side(style='thin'), bottom=Side(style='thin'))

Answer 3

There is a slight modification to answer from @Karimov
Below is how your code should be

from openpyxl.styles import Border, Side, Font, Alignment

def __format_ws__(self, ws, cell_range):
     border = Border(left=Side(border_style='thin', color='000000'),
                    right=Side(border_style='thin', color='000000'),
                    top=Side(border_style='thin', color='000000'),
                    bottom=Side(border_style='thin', color='000000'))

      rows = ws[cell_range]
      for row in rows:
          for cell in row:
              cell.border = border

A much faster way that uses list comprehension is below:

 def __format_ws__(self, ws, cell_range):

        #applying border and alignment
        font = Font(size=9)
        align=Alignment(horizontal='left', vertical='center')
        border = Border(left=Side(border_style='thin', color='000000'),
                        right=Side(border_style='thin', color='000000'),
                        top=Side(border_style='thin', color='000000'),
                        bottom=Side(border_style='thin', color='000000'))

        rows = [rows for rows in ws[cell_range]]
        flattened = [item for sublist in rows for item in sublist]
        [(setattr(cell,'border',border), setattr(cell,'font',font), setattr(cell,'alignment',align)) for cell in flattened]

The way you use it is:

self.__format_ws__(ws=writer.book.worksheets[0], cell_range='A1:G10')

Answer 4

if you need styling (borders...) for pandas excel dataframe my fork just got merged into master https://github.com/pydata/pandas/pull/2370#issuecomment-10898427

as for you borders problems. setting all borders at once does not seam to work in openpyxl.

In [34]: c.style.borders.all_borders.border_style = openpyxl.style.Border.BORDER_THIN

In [36]: c.style
'Calibri':11:False:False:False:False:'none':False:'FF000000':'none':0:'FFFFFFFF':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':0:'thin':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'general':'bottom':0:False:False:0:'General':0:'inherit':'inherit'

setting individually works ('thin':'FF000000')

In [37]: c.style.borders.top.border_style = openpyxl.style.Border.BORDER_THIN

In [38]: c.style
Out[38]: 'Calibri':11:False:False:False:False:'none':False:'FF000000':'none':0:'FFFFFFFF':'FF000000':'none':'FF000000':'none':'FF000000':'thin':'FF000000':'none':'FF000000':'none':'FF000000':0:'thin':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'general':'bottom':0:False:False:0:'General':0:'inherit':'inherit'

maybe a bug in openpyxl. but no big deal just wrap setting bottom , top, left, right in function

Answer 5

In more pythonic way for openpyxl==3.0.5:

from openpyxl.styles import Border, Side

def set_border(ws, cell_range):
    thin = Side(border_style="thin", color="000000")
    for row in ws[cell_range]:
        for cell in row:
            cell.border = Border(top=thin, left=thin, right=thin, bottom=thin)

set_border(worksheet, 'A5:C10') 

Answer 6

May be this is handy:

from openpyxl.reader.excel import load_workbook
from openpyxl.style import Border

def set_border(ws, cell_range):
    rows = ws.range(cell_range)
    for row in rows:
        row[0].style.borders.left.border_style = Border.BORDER_THIN
        row[-1].style.borders.right.border_style = Border.BORDER_THIN
    for c in rows[0]:
        c.style.borders.top.border_style = Border.BORDER_THIN
    for c in rows[-1]:
        c.style.borders.bottom.border_style = Border.BORDER_THIN

#usage example:
ws = load_workbook('example.xlsx').get_active_sheet()
set_broder(ws, "C3:H10")

It performs reasonably fast.