find the maximum number in a list using a loop

Question

So I have this list and variables:

nums = [14, 8, 9, 16, 3, 11, 5]

big = nums[0]

spot = 0

I\'m confused on how to actually do it. Please

Answer 1

To print the Index of the largest number in a list.

numbers = [1,2,3,4,5,6,9]

N = 0
for num in range(len(numbers)) :
  if numbers[num] > N :
    N = numbers[num]
print(numbers.index(N))

Answer 2

scores = [12, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27,
          28, 29, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 31, 31, 37,
          56, 75, 23, 565]

# initialize highest to zero
highest = 0

for mark in scores:
    if highest < mark:
        highest = mark

print(mark)

Answer 3

Why not simply using the built-in max() function:

>>> m = max(nums)

By the way, some answers to similar questions might be useful:

• Pythonic way to find maximum value and its index in a list?
• How to find all positions of the maximum value in a list?

Answer 4

For the Max in List Code HS I've managed to get most of the auto grader to work for me using this code:

list = [-3,-8,-2,0]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print current_max_number

def max_int_in_list():
    print "Here"

I'm not sure where the max_int_in_list goes though. It needs to have exactly 1 parameter.

Answer 5

To address your second question, you can use a for loop:

for i in range(len(list)):
    # do whatever

You should note that range() can have 3 arguments: start, end, and step. Start is what number to start with (if not supplied, it is 0); start is inclusive.. End is where to end at (this has to be give); end is exclusive: if you do range(100), it will give you 0-99. Step is also optional, it means what interval to use. If step is not provided, it will be 1. For example:

>>> x = range(10, 100, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95] # note that it does not hit 100

Since end is exclusive, to include 100, we could do:

>>> x = range(10, 101, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100] # note that it does hit 100

Answer 6

Python already has built in function for this kind of requirement.

list = [3,8,2,9]
max_number = max(list)
print max_number # it will print 9 as big number

however if you find the max number with the classic vay you can use loops.

list = [3,8,2,9]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print current_max_number #it will display 9 as big number