Python: Create strikethrough / strikeout / overstrike string type

Question

I would appreciate some help in creating a function that iterates through a string and combines each character with a strikethrough character (\\u0336). With the output bein

Answer 1

How about:

from itertools import repeat, chain

''.join(chain.from_iterable(zip(text, repeat('\u0336'))))

or even more simply,

'\u0336'.join(text) + '\u0336'

Answer 2

Edited

As pointed out by roippi other answers so far are actually correct, and this one below is wrong. Leaving it here in case others get the same wrong idea that I did.

---

Other answers so far are wrong - they do not strike out the first character of the string. Try this instead:

def strike(text):
    return ''.join([u'\u0336{}'.format(c) for c in text])

>>> print(strike('this should do the trick'))
'̶t̶h̶i̶s̶ ̶s̶h̶o̶u̶l̶d̶ ̶d̶o̶ ̶t̶h̶e̶ ̶t̶r̶i̶c̶k'

This will work in Python 2 and Python 3.

Answer 3

def strike(text):
    result = ''
    for c in text:
        result = result + c + '\u0336'
    return result

Cool effect.