XGBoost Custom Loss Functions Mismatch

后端 未结 0 1973
无人共我
无人共我 2021-01-02 19:38

The script has two losses, the squared loss L_a = (y-F(x))^2 and the same loss but with a 0.5 factor: L_b = 0.5*(y-F(x))^2. Using L_a gets me trees with one splits (even if

相关标签:
回答
  • 消灭零回复
提交回复
热议问题