List CSS custom properties (CSS Variables)

Question

I\'ve set some CSS custom properties in my stylesheet:

:root {
    --bc: #fff;
    --bc-primary: #eee;
    --bc-secondary: #ffffd;
}

I can re

Answer 1

Based on LGSon's answer here is something similar but using map, filter, and flat to make it easier to read line by line.

const variables = [].slice.call(document.styleSheets)
    .map(styleSheet => [].slice.call(styleSheet.cssRules))
    .flat()
    .filter(cssRule => cssRule.selectorText === ':root')
    .map(cssRule => cssRule.cssText.split('{')[1].split('}')[0].trim().split(';'))
    .flat()
    .filter(text => text !== "")
    .map(text => text.split(':'))
    .map(parts => ({key: parts[0].trim(), value: parts[1].trim() }))
;

console.log(variables);

:root {
    --foo: #fff;
    --bar: #aaa
}

Answer 2

One possible solution would be to parse the document.styleSheets, and then split the rules into properties/values

var allCSS = [].slice.call(document.styleSheets)
  .reduce(function(prev, styleSheet) {
    if (styleSheet.cssRules) {
      return prev + [].slice.call(styleSheet.cssRules)
        .reduce(function(prev, cssRule) {        
          if (cssRule.selectorText == ':root') {
            var css = cssRule.cssText.split('{');
            css = css[1].replace('}','').split(';');
            for (var i = 0; i < css.length; i++) {
              var prop = css[i].split(':');
              if (prop.length == 2 && prop[0].indexOf('--') == 1) {
                console.log('Property name: ', prop[0]);
                console.log('Property value:', prop[1]);
              }              
            }
          }
        }, '');
    }
  }, '');

:root {
    --bc: #fff;
    --bc-primary: #eee;
    --bc-secondary: #ffffd;
}