Is it possible to make a letter range in python?

Question

Is there a way to do a letter range in python like this:

for x in range(a,h,)

Answer 1

Malcom's example works great, but there is a little problem due to how Pythons list comparison works. If 'A' to "Z" or some character to "ZZ" or "ZZZ" will cause incorrect iteration.

Here "AA" < "Z" or "AAA" < "ZZ" will become false.

In Python [0,0,0] is smaller than [1,1] when compared with "<" or ">" operator.

So below line

while len(start_int_list) < len(end_int_list) or start_int_list <= end_int_list:

should be rewritten as below

while len(start_int_list) < len(end_int_list) or\
        ( len(start_int_list) == len(end_int_list) and start_int_list <= end_int_list):

It is well explained here https://docs.python.org/3/tutorial/datastructures.html#comparing-sequences-and-other-types

I rewrote the code example below.

def strange(start, end_or_len, sequence='ABCDEFGHIJKLMNOPQRSTUVWXYZ'):

    seq_len = len(sequence)
    start_int_list = [sequence.find(c) for c in start]
    if isinstance(end_or_len, int):
        inclusive = True
        end_int_list = list(start_int_list)
        i = len(end_int_list) - 1
        end_int_list[i] += end_or_len - 1
        while end_int_list[i] >= seq_len:
            j = end_int_list[i] // seq_len
            end_int_list[i] = end_int_list[i] % seq_len
            if i == 0:
                end_int_list.insert(0, j-1)
            else:
                i -= 1
                end_int_list[i] += j
    else:
        end_int_list = [sequence.find(c) for c in end_or_len]

    while len(start_int_list) < len(end_int_list) or\
         (len(start_int_list) == len(end_int_list) and start_int_list <= end_int_list):**
        yield ''.join([sequence[i] for i in start_int_list])
        i = len(start_int_list)-1
        start_int_list[i] += 1
        while start_int_list[i] >= seq_len:
            start_int_list[i] = 0
            if i == 0:
                start_int_list.insert(0,0)
            else:
               i -= 1
                start_int_list[i] += 1

Anyway, Malcom's code example is a great illustration of how iterator in Python works.

Answer 2

this is easier for me at least to read/understand (and you can easily customize which letters are included, and in what order):

letters = 'abcdefghijklmnopqrstuvwxyz'
for each in letters:
    print each

result:
a
b
c
...
z