Is it possible to make a letter range in python?

Question

Is there a way to do a letter range in python like this:

for x in range(a,h,)

Answer 1

You can use ord() to convert the letters into character ordinals and back:

def char_range(start, end, step=1):
    for char in range(ord(start), ord(end), step):
        yield chr(char)

It seems to work just fine:

>>> ''.join(char_range('a', 'z'))
    'abcdefghijklmnopqrstuvwxy'

Answer 2

how about slicing an already pre-arranged list?

import string

s = string.ascii_lowercase
print( s[ s.index('b'):s.index('o')+1 ] )

Answer 3

Emanuele's solution is great as long as one is only asking for a range of single characters, which I will admit is what the original questioner posed. There are also solutions out there to generate all multi-character combinations: How to generate a range of strings from aa... to zz. However I suspect that someone who wants a character like range function might want to be able to deal with generating an arbitrary range from say 'y' to 'af' (rolling over from 'z' to 'aa'). So here is a more general solution that includes the ability to either specify the last member of the range or its length.

def strange(start, end_or_len, sequence='ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
    """Create a generator of a range of 'sequential' strings from
    start to end_or_len if end_or_len is a string or containing
    end_or_len entries if end_or_len is an integer.

    >>> list(strange('D', 'F'))
    ['D', 'E', 'F']
    >>> list(strange('Y', 'AB'))
    ['Y', 'Z', 'AA', 'AB']
    >>> list(strange('Y', 4))
    ['Y', 'Z', 'AA', 'AB']
    >>> list(strange('A', 'BAA', sequence='AB'))
    ['A', 'B', 'AA', 'AB', 'BA', 'BB', 'AAA', 'AAB', 'ABA', 'ABB', 'BAA']
    >>> list(strange('A', 11, sequence='AB'))
    ['A', 'B', 'AA', 'AB', 'BA', 'BB', 'AAA', 'AAB', 'ABA', 'ABB', 'BAA']
    """
    seq_len = len(sequence)
    start_int_list = [sequence.find(c) for c in start]
    if isinstance(end_or_len, int):
        inclusive = True
        end_int_list = list(start_int_list)
        i = len(end_int_list) - 1
        end_int_list[i] += end_or_len - 1
        while end_int_list[i] >= seq_len:
            j = end_int_list[i] // seq_len
            end_int_list[i] = end_int_list[i] % seq_len
            if i == 0:
                end_int_list.insert(0, j-1)
            else:
                i -= 1
                end_int_list[i] += j
    else:
        end_int_list = [sequence.find(c) for c in end_or_len]
    while len(start_int_list) < len(end_int_list) or start_int_list <= end_int_list:
        yield ''.join([sequence[i] for i in start_int_list])
        i = len(start_int_list)-1
        start_int_list[i] += 1
        while start_int_list[i] >= seq_len:
            start_int_list[i] = 0
            if i == 0:
                start_int_list.insert(0,0)
            else:
                i -= 1
                start_int_list[i] += 1


if __name__ =='__main__':
    import doctest
    doctest.testmod()

Answer 4

There is no built in letter range, but you can write one:

def letter_range(start, stop):
    for c in xrange(ord(start), ord(stop)):
        yield chr(c)


for x in letter_range('a', 'h'):
    print x,

prints:

a b c d e f g

Answer 5

import string

def letter_range(f,l,al = string.ascii_lowercase):
    for x in al[al.index(f):al.index(l)]:
        yield x

print ' '.join(letter_range('a','h'))

result

a b c d e f g

Answer 6

Something like:

[chr(i) for i in range(ord('a'),ord('h'))]

Will give a list of alphabetical characters to iterate through, which you can then use in a loop

for x in [chr(i) for i in range(ord('a'),ord('h'))]:
    print(x)

or this will do the same:

for x in map(chr, range(*map(ord,['a', 'h']))):
    print(x)