Sort list of strings by integer suffix in python

Question

I have a list of strings:

[song_1, song_3, song_15, song_16, song_4, song_8]

I would like to sort them by the # at the end, unfortunately s

Answer 1

Well, you want to sort by the filename first, then on the int part:

def splitter( fn ):
    try:
        name, num = fn.rsplit('_',1)  # split at the rightmost `_`
        return name, int(num)
    except ValueError: # no _ in there
        return fn, None

sorted(the_list, key=splitter)

Answer 2

def number_key(name):
   parts = re.findall('[^0-9]+|[0-9]+', name)
   L = []
   for part in parts:
       try:
          L.append(int(part))
       except ValueError:
          L.append(part)
   return L
sorted(your_list, key=number_key)

Answer 3

You're close.

sorted(the_list, key = lambda x: int(x.split("_")[1]))

should do it. This splits on the underscore, takes the second part (i.e. the one after the first underscore), and converts it to integer to use as a key.

Answer 4

sorted(the_list, key = lambda k: int(k.split('_')[1]))