I\'m relatively new to JavaScript and I thought I knew how callback functions worked but after a couple of hours of searching the web I still do not understand why my code i
The first A in ajax is for Asynchronous, which means that by the time you are debugging the array, the result still hasn't been delivered. Array is undefined at the point of displaying it's value. You need to do the console.debug below array = data.
The success
function doesn't execute immediately, but only after the HTTP-response arrives. Therefore, array
is still undefined
at this point. If you want to perform operations on the HTTP-response data, do it from within the success
function, or alternatively, define that operation inside of a function and then invoke that function from within the success
callback.
The problem here is that console.log
executes synchronously while the ajax call executes asynchronously. Hence it runs before the callback completes so it still sees array
as undefined
because success
hasn't run yet. In order to make this work you need to delay the console.log
call until after success
completes.
$(document).ready(function() {
var array;
var runLog = function() {
console.log(array);
};
$.ajax({
type: 'GET',
url: 'include/load_array.php',
dataType: 'json',
success: function(data){
array = data;
runlog();
}});
});
Try calling a function to set this variable after your success
:
var array;
var goodToProceed = function(myArr) {
console.debug(myArr);
};
$.ajax({
type: 'GET',
url: 'include/load_array.php',
dataType: 'json',
success: function(data){
goodToProceed(data);
},
error: function(jqXHR, textStatus, errorThrown){
alert("Error loading the data");
}
});
AJAX is asynchronous. You are setting the array
variable, but not until after that debug
executes. Making an AJAX call sends a request but then continues on in the code. At some later point, the request returns and your success
or error
functions execute.