How to map a DTO to an existing JPA entity?

后端 未结 4 1421
伪装坚强ぢ
伪装坚强ぢ 2021-01-02 10:49

I\'m trying to map a Java DTO object to an existing JPA entity object without having to do something like the following:

public MyEntity mapToMyEntity(SomeDT         


        
相关标签:
4条回答
  • 2021-01-02 11:20

    Currently ModelMapper supports mapping also to an existing object.

    It is possible to do the following (for a pseudo Spring example):

    MyEntity mye = repository.finById(id);
    ModelMapper mm = new ModelMapper();    
    mm.map(myDTO, mye);
    repository.save(mye):
    

    I am using version 2.3.1 but earlier versions might support this functionality also

    0 讨论(0)
  • 2021-01-02 11:26

    You can use dozer mapper or gson.

    DozerMapper ex:

    Mapper mapper = DozerBeanMapperBuilder.createDefault();
    DestinationObject destObject = mapper.map(sourceObject,DestinationClassName.class);
    

    You can check github page for more information

    0 讨论(0)
  • 2021-01-02 11:26

    You can define next class:

    public class ObjectMapperUtils {
    
        private static ModelMapper modelMapper = new ModelMapper();
    
        /**
         * Model mapper property setting are specified in the following block.
         * Default property matching strategy is set to Strict see {@link MatchingStrategies}
         * Custom mappings are added using {@link ModelMapper#addMappings(PropertyMap)}
         */
        static {
            modelMapper = new ModelMapper();
            modelMapper.getConfiguration().setMatchingStrategy(MatchingStrategies.STRICT);
        }
    
        /**
         * Hide from public usage.
         */
        private ObjectMapperUtils() {
        }
    
        /**
         * <p>Note: outClass object must have default constructor with no arguments</p>
         *
         * @param <D>      type of result object.
         * @param <T>      type of source object to map from.
         * @param entity   entity that needs to be mapped.
         * @param outClass class of result object.
         * @return new object of <code>outClass</code> type.
         */
        public static <D, T> D map(final T entity, Class<D> outClass) {
            return modelMapper.map(entity, outClass);
        }
    
        /**
         * <p>Note: outClass object must have default constructor with no arguments</p>
         *
         * @param entityList list of entities that needs to be mapped
         * @param outCLass   class of result list element
         * @param <D>        type of objects in result list
         * @param <T>        type of entity in <code>entityList</code>
         * @return list of mapped object with <code><D></code> type.
         */
        public static <D, T> List<D> mapAll(final Collection<T> entityList, Class<D> outCLass) {
            return entityList.stream()
                    .map(entity -> map(entity, outCLass))
                    .collect(Collectors.toList());
        }
    
        /**
         * Maps {@code source} to {@code destination}.
         *
         * @param source      object to map from
         * @param destination object to map to
         */
        public static <S, D> D map(final S source, D destination) {
            modelMapper.map(source, destination);
            return destination;
        }
    }
    

    And use it for your needs:

    MyEntity entity = ObjectMapperUtils.map(dto, existingEntity);
    
    0 讨论(0)
  • 2021-01-02 11:34

    Translated from Portuguese

    https://pt.stackoverflow.com/questions/166438/dto-assembler-como-utiliza-lo-realmente

    Use Pattern Assembler: You could convert Entity to DTO through the assembler pattern but it is wrong (I think), it breaks the sense of the DTO which is a standard for transferring objects. See that it can be composed by of several entities. The correct thing is to use set methods of the instances of the objects in the classes of services, taking the DTO's and assembling them as entities, it is simply because you are working correctly with the standard.

    But it has a way that even if it being wrong it would work, but only a 1 x 1 association between entity x DTO, use Guava function.

    Eg: to convert Translate to transform into objects and lists with

    import java.util.ArrayList;
    import java.util.List;
    import com.google.common.base.Function;
    
        /**
         * Classe de transformação para popular os dados em DTOs, seguindo o pattern
         * Transfer Object Assembler.
         */
        public class Transformer {
    
            /**
             * Executa a transformação de um objeto para um DTO.
             * 
             * @param from
             * @param function
             * @return <F, T> T
             */
            public static <F, T> T transform(F from, Function<? super F, ? extends T> function) {
                return (from == null) ? null : function.apply(from);
            }
    
            /**
             * Executa a transformação de uma lista de objetos para uma lista de DTOs.
             * 
             * @param fromList
             * @param function
             * @return <F, T> List<T>
             */
            public static <F, T> List<T> transform(List<F> source, Function<? super F, ? extends T> function) {
                List<T> out = new ArrayList<>(source.size());
    
                for (F from : source) {
                    out.add(function.apply(from));
                }    
                return out;
            }    
        }
    

    Pattern assembler:

    import java.util.List;
    import br.com.myapp.model.dto.AuthUserDTO;
    import br.com.myapp.model.entity.AuthUser;
    import com.google.common.base.Function;
    import com.google.common.collect.Lists;
    
    /**
     * Classe que transforma entidade USUARIOS em DTO.
     * 
     * @author Dilnei Cunha
     */
    public class AuthUserDTOAssembler implements Function<AuthUser, AuthUserDTO>{
    
        /**
         * Método responsável por fazer a conversão da entidade USUARIOS em um AuthUserDTO.
         */
    @Override
    public AuthUserDTO apply(AuthUser e) {
    
        AuthGroupDTO groupDTO = Transformer.transform(e.getAuthGroup(), new  AuthGroupDTOAssembler());
    
        return new AuthUserDTO(e.getId(),
                           e.getName(),
                           e.getPassword(),
                           e.getEmail(),
                           e.getCreationDate(),
                           e.getLastModificationdate(),
                           e.getLastAccessDate(),
                           e.getAtivo(),
                           e.getUserName(),
                           e.getRamal(),
                           groupDTO);
        }
    }
    

    What would be the service that would use these patterns ...

    /**
     * Método responsável por buscar um AuthUserDTO pelo ID do usuário.
     */
    @Override
    public AuthUserDTO findById(Long id) {
        return Transformer.transform(authUserRepository.findUserById(id), new AuthUserDTOAssembler());
    }
    

    Now let's do the inverse process of turning one or a list of DTOs into objects, but keep in mind that the association was 1x1. To do this, simply reverse the objects in the implementation of the function, eg:

    import java.util.List;
    import br.com.myapp.model.dto.AuthUserDTO;
    import br.com.myapp.model.entity.AuthUser;
    import com.google.common.base.Function;
    import com.google.common.collect.Lists;
    
    /**
     * @author Dilnei Cunha
     */
    public class AuthUserAssembler implements Function<AuthUserDTO, AuthUser>{
    
    @Override
    public AuthUser apply(AuthUserDTO e) {
    
            AuthGroup group = Transformer.transform(e.getAuthGroupDTO(), new  AuthGroupAssembler());
    
            return new AuthUser(e.getId(),
                               e.getName(),
                               e.getPassword(),
                               e.getEmail(),
                               e.getCreationDate(),
                               e.getLastModificationdate(),
                               e.getLastAccessDate(),
                               e.getAtivo(),
                               e.getUserName(),
                               e.getRamal(),
                               group);
            }
        }
    
    0 讨论(0)
提交回复
热议问题