I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed.
How do I do I pass the model to this st
Put the object required by the partial into Viewdata and use ist in the view as input for the partial.
public ActionResult Test()
{
ViewData["DataForPartial"] = new PartialDataObject();
return View("Test")
}
In the view use:
<% Html.RenderPartial("PartialView",ViewData["DataForPartial"]); %>
But anyway: There is no reason no to have a stronly typed view.
You should extend your model so that it can provide all necessary fields for the view (this is called ViewModel) or you provide them seperately with ViewData.
public ActionResult Test()
{
MyData = new Data();
MyData.One = 1;
ViewData["someData"]=MyData;
return View();
}
then:
<% Html.RenderPartial("PartialView",ViewData["someData"]); %>
ViewData is a nice losely typed dictionary