Wait for all Operations in queue to finish before performing task

Question

I have an Operation subclass and Operation queue with maxConcurrentOperationCount = 1.

This performs my operations in a sequential order that i add them which is goo

Answer 1

You can use operation dependencies to initiate some operation upon the completion of a series of other operations:

let queue = OperationQueue()

let completionOperation = BlockOperation {
    // all done
}

for object in objects {
    let operation = ...
    completionOperation.addDependency(operation)
    queue.addOperation(operation)
}

OperationQueue.main.addOperation(completionOperation)  // or, if you don't need it on main queue, just `queue.addOperation(completionOperation)`

Or, in iOS 13 and later, you can use barriers:

let queue = OperationQueue()

for object in objects {
    queue.addOperation(...)
}

queue.addBarrierBlock {
    DispatchQueue.main.async {
        // all done
    }
}

Answer 2

Set the maximum number of concurrent operations to 1

operationQueue.maxConcurrentOperationCount = 1

then each operation will be executed in order (as if each was dependent on the previous one) and your completion operation will execute at the end.

Answer 3

A suitable solution is KVO

First before the loop add the observer (assuming queue is the OperationQueue instance)

queue.addObserver(self, forKeyPath:"operations", options:.new, context:nil)

Then implement

override func observeValue(forKeyPath keyPath: String?, of object: Any?, change: [NSKeyValueChangeKey : Any]?, context: UnsafeMutableRawPointer?) {
    if object as? OperationQueue == queue && keyPath == "operations" {
        if queue.operations.isEmpty {
            // Do something here when your queue has completed
            self.queue.removeObserver(self, forKeyPath:"operations")
        }
    } else {
        super.observeValue(forKeyPath: keyPath, of: object, change: change, context: context)
    }
}

Edit:

In Swift 4 it's much easier

Declare a property:

var observation : NSKeyValueObservation?

and create the observer

observation = queue.observe(\.operationCount, options: [.new]) { [unowned self] (queue, change) in
    if change.newValue! == 0 {
        // Do something here when your queue has completed
        self.observation = nil
    }
}

Answer 4

I use the next solution:

private let queue = OperationQueue()

private func addOperations(_ operations: [Operation], completionHandler: @escaping () -> ()) {
    DispatchQueue.global().async { [unowned self] in
        self.queue.addOperations(operations, waitUntilFinished: true)
        DispatchQueue.main.async(execute: completionHandler)
    }
}

Answer 5

Code at the end of the queue refer to this link

NSOperation and NSOperationQueue are great and useful Foundation framework tools for asynchronous tasks. One thing puzzled me though: How can I run code after all my queue operations finish? The simple answer is: use dependencies between operations in the queue (unique feature of NSOperation). It's just 5 lines of code solution.

NSOperation dependency trick with Swift it is just easy to implement as this:

extension Array where Element: NSOperation {
/// Execute block after all operations from the array.
func onFinish(block: () -> Void) {
    let doneOperation = NSBlockOperation(block: block)
    self.forEach { [unowned doneOperation] in doneOperation.addDependency($0) }
    NSOperationQueue().addOperation(doneOperation)
}}

Answer 6

My solution is similar to that of https://stackoverflow.com/a/42496559/452115, but I don't add the completionOperation in the main OperationQueue but into the queue itself. This works for me:

var a = [Int](repeating: 0, count: 10)

let queue = OperationQueue()

let completionOperation = BlockOperation {
    print(a)
}

queue.maxConcurrentOperationCount = 2
for i in 0...9 {
    let operation = BlockOperation {
        a[i] = 1
    }
    completionOperation.addDependency(operation)
    queue.addOperation(operation)
}

queue.addOperation(completionOperation)

print("Done