What is lifetime of lambda-derived implicit functors in C++?

Question

The question is simple: what is lifetime of that functor object that is automatically generated for me by the C++ compiler when I write a lambda-expression?

I did a

Answer 1

Depends on how you capture your variables. If you capture them by reference ([&]) and they go out of scope, the references will be invalid, just like normal references. Capture them by value ([=]) if you want to make sure they outlife their scope.