How to create an Expression tree to do the same as “StartsWith”

Question

Currently, I have this method to compare two numbers

Private Function ETForGreaterThan(ByVal query As IQueryable(Of T), ByVal propertyValue As Object, ByVal          


        

Answer 1

It's not an operator, but a method, so you can call it with Expression.Call(), where the methodinfo parameter will be typeof(string).GetMethod("StartsWith").

Answer 2

using System;
using System.Linq;
using System.Linq.Expressions;
using System.Reflection;

namespace WindowsFormsApplication1
{
    static class Program
    {
        [STAThread]
        static void Main()
        {
            using (var context = new NorthwindEntities())
            {
                PropertyInfo propertyInfo = typeof(Customer).GetProperty("CustomerID"); 

                IQueryable<Customer> query = context.Customers;
                query = ETForStartsWith<Customer>(query, "A", propertyInfo); 
                var list = query.ToList();
            }
        }

        static IQueryable<T> ETForStartsWith<T>(IQueryable<T> query, string propertyValue, PropertyInfo propertyInfo)
        {
            ParameterExpression e = Expression.Parameter(typeof(T), "e");
            MemberExpression m = Expression.MakeMemberAccess(e, propertyInfo);
            ConstantExpression c = Expression.Constant(propertyValue, typeof(string));
            MethodInfo mi = typeof(string).GetMethod("StartsWith", new Type[] { typeof(string) });
            Expression call = Expression.Call(m, mi, c);

            Expression<Func<T, bool>> lambda = Expression.Lambda<Func<T, bool>>(call, e); 
            return query.Where(lambda);
        }
    }
}