Static keyword in function declaration can be missing in function definition?

后端 未结 5 2021
深忆病人
深忆病人 2021-01-02 03:36

I want to have a static function which I declare in my .c file before defining it:

//file a.c version 1
static int foo();
...
static int foo()
{
...
}


        
相关标签:
5条回答
  • 2021-01-02 04:07

    The static attribute changes the visibility to the compilation unit. This allows to use the same name in different files for different purposes. You should use the static only once. If you have a prototype, you must do here.

    When you are asking for C++ you should not use static but anonymous namespace to make the symbold private for the compilation unit:

    namespace {
        int foo();
    }
    
    void bar()
    {
        foo();
    }
    
    0 讨论(0)
  • 2021-01-02 04:08

    7.1.1/7:

    The linkages implied by successive declarations for a given entity shall agree. That is, within a given scope, each declaration declaring the same object name or the same overloading of a function name shall imply the same linkage.

    7.1.1/6: (Thanks Steve - this is also needed for the answer to be clear)

    A name declared in a namespace scope without a storage-class-specifier has external linkage unless it has internal linkage because of a previous declaration and provided it is not declared const. Objects declared const and not explicitly declared extern have internal linkage.

    Yes, those two are the same.

    This however is invalid:

    int foo();
    
    static int foo() {
      return 0;
    }
    
    0 讨论(0)
  • 2021-01-02 04:17

    As a sidenote, C++ provides a superior alternative to static. You can also use unnamed namespace here

    Example,

    namespace 
    {  
       void f()
       {
       }
    }
    

    See these:

    Superiority of unnamed namespace over static?
    Why an unnamed namespace is a "superior" alternative to static?

    0 讨论(0)
  • 2021-01-02 04:20

    static - in this context - only affects the scope, when you declare a function static it has file scope. So you can easily check if it is the same by trying to access the function from another source.

    that way we avoid the discussions about compiler language etc.

    0 讨论(0)
  • 2021-01-02 04:30

    Yes 7.1.1/6

    A name declared in a namespace scope without a storage-class-specifier has external linkage unless it has internal linkage because of a previous declaration and provided it is not declared const.

    See also the examples of 7.1.1/7

    0 讨论(0)
提交回复
热议问题