How to use like in XPath?

Question

I have a page that searches with filters. I have this code for example,

xmlTempResultSearch = xmlResidentListDisplay.selectNodes(\"//PeopleList/Row[@LastName         


        

Answer 1

You can use start-with function and not function. Reference:

http://www.w3schools.com/xpath/xpath_functions.asp

xmlTempResultSearch = xmlResidentListDisplay.selectNodes("//PeopleList/Row[not(starts-with(@LastName,'"+ txtSearch.value +"'))]");

Answer 2

you can use contains() function of XPath:

xmlTempResultSearch = xmlResidentListDisplay.selectNodes("//PeopleList/Row[not(contains(@LastName,'"+txtSearch.value+"'))]");

Answer 3

You can use all of the XPath (1.0) string functions. If you have XPath 2.0 available, then you can even use RegEx.

contains()

starts-with()

substring()

substring-before()

substring-after()

concat()

translate()

string-length()

There is no **ends-with() in XPath 1.0, but it can easily be expressed with this XPath 1.0 expression**:

substring($s, string-length($s) - string-length($t) +1) = $t

is true() exactly when the string $s ends with the string $t.