I\'m trying to serve a static file using flask. I don\'t know how to use the url_for function. All my routes generating dynamic content are working fine, I\'ve imported url_
You are getting the correct output for what you are doing. url_for
generates the url for the arguments you give it. In your case, you are generating the url for the hi.html
file in the static
directory. If you want to actually output the file, you would want to
from flask import render_template, url_for
...
return render_template(url_for("static", filename="hi.html"))
But at this point, your static directory would need to be under the templates directory (where ever that is configured to live).
If you are going to be serving static html files like this, then my suggestion would be to serve them outside of the flask application by routing traffic to /static/.*
directly from your web server. There are plenty of examples on the web for doing this using nginx or apache.
url_for
just returns, precisely, the URL for that file. It sounds like you want to redirect
to the URL for that file. Instead, you are just sending the text of the URL to the client as a response.
from flask import url_for, redirect
@app.route('/')
def home():
return redirect(url_for('static', filename='hi.html'))