How can i delete an element in an array and then shift the array in Shell Script?

Question

First let me state my problem clearly:

Ex: Let\'s pretend this is my array, (the elements don\'t matter as in my actual code they vary):

array=(jim         


        

Answer 1

See http://www.thegeekstuff.com/2010/06/bash-array-tutorial

10. Remove an Element from an Array

...

Unix=('Debian' 'Red hat' 'Ubuntu' 'Suse' 'Fedora' 'UTS' 'OpenLinux');

pos=3

Unix=(${Unix[@]:0:$pos} ${Unix[@]:$(($pos + 1))})

This contracts the array around pos, which the original poster wanted.

Answer 2

Try this:

$ array=( "one two" "three four" "five six" )
$ unset array[1]
$ array=( "${array[@]}" )
$ echo ${array[0]}
one two
$ echo ${array[1]}
five six

Shell arrays aren't really intended as data structures that you can add and remove items from (they are mainly intended to provide a second level of quoting for situations like

arr=( "one two" "three four" )
somecommand "${arr[@]}"

to provide somecommand with two, not four, arguments). But this should work in most situations.

Answer 3

Try this:

user@pc:~$ array=(jim 0 26 chris billy 78 hello foo bar)
user@pc:~$ for itm2rm in chris 78 hello; do array=(\`echo ${array[@]} | sed "s/\<${itm2rm}\>//g"\`); done ; echo ${array[@]}
jim 0 26 billy foo bar

Answer 4

this post had been revised and moved to its own post as a more in-depth tutorial how to remove an array element correctly in a for loop