bash method to remove last 4 columns from csv file

Question

Is there a way to use bash to remove the last four columns for some input CSV file? The last four columns can have fields that vary in length from line to line so it is not

Answer 1

cat data.csv | rev | cut -d, -f-5 | rev

rev reverses the lines, so it doesn't matter if all the rows have the same number of columns, it will always remove the last 4. This only works if the last 4 columns don't contain any commas themselves.

Answer 2

This awk solution in a hacked way

awk -F, 'OFS=","{for(i=NF; i>=NF-4; --i) {$i=""}}{gsub(",,,,,","",$0);print $0}' temp.txt