What\'s the difference between /
and \\
for division in VB.NET?
My code gives very different answers depending on which I use. I\'ve seen b
There are two ways to divide numbers. The fast way and the slow way. A lot of compilers try to trick you into doing it the fast way. C# is one of them, try this:
using System;
class Program {
static void Main(string[] args) {
Console.WriteLine(1 / 2);
Console.ReadLine();
}
}
Output: 0
Are you happy with that outcome? It is technically correct, documented behavior when the left side and the right side of the expression are integers. That does a fast integer division. The IDIV instruction on the processor, instead of the (infamous) FDIV instruction. Also entirely consistent with the way all curly brace languages work. But definitely a major source of "wtf happened" questions at SO. To get the happy outcome you would have to do something like this:
Console.WriteLine(1.0 / 2);
Output: 0.5
The left side is now a double, forcing a floating point division. With the kind of result your calculator shows. Other ways to invoke FDIV is by making the right-side a floating point number or by explicitly casting one of the operands to (double).
VB.NET doesn't work that way, the / operator is always a floating point division, irrespective of the types. Sometimes you really do want an integer division. That's what \
does.
10 / 3 = 3.333
10 \ 3 = 3 (the remainder is ignored)
10 / 3 = 3.33333333333333, assigned to integer = 3
10 \ 3 = 3, assigned to integer = 3
20 / 3 = 6.66666666666667, assigned to integer = 7
20 \ 3 = 6, assigned to integer = 6
Code for the above:
Dim a, b, c, d As Integer
a = 10 / 3
b = 10 \ 3
c = 20 / 3
d = 20 \ 3
Debug.WriteLine("10 / 3 = " & 10 / 3 & ", assigned to integer = " & a)
Debug.WriteLine("10 \ 3 = " & 10 \ 3 & ", assigned to integer = " & b)
Debug.WriteLine("20 / 3 = " & 20 / 3 & ", assigned to integer = " & c)
Debug.WriteLine("20 \ 3 = " & 20 \ 3 & ", assigned to integer = " & d)
/ Division
\ Integer Division