Invalid initialization of non-const reference of type

Question

In the following code, I\'m not able to pass a temporary object as argument to the printAge function:

struct Person {
  int age;
  Person(int _a         


        

Answer 1

Or, if you have a C++11-compliant compiler, can use the so called universal reference approach, which, via reference collapsing rules, can bind to both lvalue and rvalue references:

#include <iostream>
using namespace std;

struct Person {
  int age;
  Person(int _age): age(_age) {}
};

template<typename T> // can bind to both lvalue AND rvalue references
void printAge(T&& person) {
   cout << "Age: " << person.age << endl;
}

int main () {
  Person p(50);
  printAge(Person(50));  // works now
  printAge(p);
  return 0;
}

Or, in C++14,

void printAge(auto&& person) {
   cout << "Age: " << person.age << endl;
}

Answer 2

Your code doesn't work if you run g++ or gcc compilers. You need to add const to void printAge(const Person &person). However, in Visual Studio it will work fine. I've tested for VS2010 and VS2012 and in both the following code works fine.

 #include<iostream>

using namespace std;
struct Person {
  int age;
  Person(int _age): age(_age) {}
};

void printAge(Person &person) {
   cout << "Age: " << person.age << endl;
}

int main () {
  Person p(50);
  printAge(Person(50));  // DOES NOT fail!
  printAge(p);
  return 0;
}

Answer 3

Simply make your print function take your argument by const&. This is also logically right as it doesn't modify your argument.

void printAge(const Person &person) {
   cout << "Age: " << person.age << endl;
}

The actual problem is the other way around. You are passing a temporary(rvalue) to a function which expects an lvalue.