Pythonic way to iterate through a range starting at 1

Question

Currently if I want to iterate 1 through n I would likely use the following method:

for _ in rang         


        

Answer 1

for i in range(n):
    print(i+1)

This will output:

1 
2
...
n    

Answer 2

From the documentation:

range([start], stop[, step])

The start defaults to 0, the step can be whatever you want, except 0 and stop is your upper bound, it is not the number of iterations. So declare n to be whatever your upper bound is correctly and you will not have to add 1 to it.

Answer 3

range(1, n+1) is common way to do it, but if you don't like it, you can create your function:

def numbers(first_number, last_number, step=1):
    return range(first_number, last_number+1, step)

for _ in numbers(1, 5):
    print(_)

Answer 4

range(1, n+1) is not considered duplication, but I can see that this might become a hassle if you were going to change 1 to another number.

This removes the duplication using a generator:

for _ in (number+1 for number in range(5)):
    print(_)

Answer 5

Not a general answer, but for very small ranges (say, up to five), I find it much more readable to spell them out in a literal:

for _ in [1,2,3]:
    print _

That's true even if it does start from zero.