Convert String Array into Int Array Swift 2?

Question

[Xcode 7.1, iOS 9.1]

I have an array: var array: [String] = [\"11\", \"43\", \"26\", \"11\", \"45\", \"40\"]

I want to convert that (each index

Answer 1

Use the map function

let array = ["11", "43", "26", "11", "45", "40"]
let intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]

Within a class like UIViewController use

let array = ["11", "43", "26", "11", "45", "40"]
var intArray = Array<Int>!

override func viewDidLoad() {
  super.viewDidLoad()
  intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]
}

If the array contains different types you can use flatMap (Swift 2) or compactMap (Swift 4.1+) to consider only the items which can be converted to Int

let array = ["11", "43", "26", "Foo", "11", "45", "40"]
let intArray = array.compactMap { Int($0) } // [11, 43, 26, 11, 45, 40]

Answer 2

Swift 4, 5:

The instant way if you want to convert string numbers into arrays of type int (in a particular case i've ever experienced):

let pinString = "123456"
let pin = pinString.map { Int(String($0))! }

And for your question is:

let pinArrayString = ["1","2","3","4","5","6"]
let pinArrayInt = pinArrayString.map { Int($0)! }

Answer 3

i suggest a little bit different approach

let stringarr = ["1","foo","0","bar","100"]
let res = stringarr.map{ Int($0) }.enumerate().flatMap { (i,j) -> (Int,String,Int)? in
    guard let value = j else {
        return nil
    }
    return (i, stringarr[i],value)
}
// now i have an access to (index in orig [String], String, Int) without any optionals and / or default values
print(res)
// [(0, "1", 1), (2, "0", 0), (4, "100", 100)]

Answer 4

Swift 4, 5:

Use compactMap with cast to Int, solution without '!'.

let array = ["1","foo","0","bar","100"]
let arrayInt = array.compactMap { Int($0) }

print(arrayInt)
// [1, 0, 100]