I\'d like to round integers down to their nearest 1000 in Java.
So for example:
You could divide the number by 1000, apply Math.floor, multiply by 1000 and cast back to integer.
Simply divide by 1000 to lose the digits that are not interesting to you, and multiply by 1000:
i = i/1000 * 1000
Or, you can also try:
i = i - (i % 1000)
int i = Math.floorDiv(-13623, 1000) * 1000
//i => -14000
The above code will always round down (towards negative infinity) assuming the divisor (1000 in the example) is positive.
The other answer (i = i/1000 * 1000
) rounds down when i
is positive, but up when i
is negative.
-13623 / 1000 * 1000 == -13000
There is also a version of Math.floorDiv
for long
s which will work for very large numbers where the Math.floor
method might fail due to the precision of double
.
There are also Math.floorMod
methods to go with the floorDiv
s which might allow you to shorten it a bit:
int i = -13623;
i -= Math.floorMod(i, 1000);
//i => -14000