Python csv without header

Question

With header information in csv file, city can be grabbed as:

city = row[\'city\']

Now how to assume that csv file does not have headers, th

Answer 1

You can use pandas.read_csv() function similarly to the way @nosklo describes, as follows:

df = pandas.read_csv("A2", header=None)
print df[0]

or

df = pandas.read_csv("A2", header=None, names=(['city']))
print df['city']

Answer 2

You can still use your line, if you declare the headers yourself, since you know it:

with open('data.csv') as f:
    cf = csv.DictReader(f, fieldnames=['city'])
    for row in cf:
        print row['city']

For more information check csv.DictReader info in the docs.

Another option is to just use positional indexing, since you know there's only one column:

with open('data.csv') as f:
    cf = csv.reader(f)
    for row in cf:
        print row[0]

Answer 3

I'm using a pandas dataframe object:

df=pd.read_sql(sql_query,data_connection)
df.to_csv(filename, header=False, index=False)

Don't know if that is the most Pythonic approach, but it gets the job done.