Using sed to match a pattern and deleting from the line to the end of the file

Question

I\'m trying to match a pattern from piped input and/or a file, and then remove from the matched lines to the end of the file, inclusive. I\'ve looked everywhere, but can\'t

Answer 1

Here's a regular expression that I think will do what you want it to: ^(?:(?!Files:).)+|\s*-----THIS STUFF IS USELESS-----.+ Make sure to set the dotall flag.

Demo+explanation: http://regex101.com/r/xF2fN5

You only need to run this one expression.

Answer 2

why not

 sed '/^-----THIS STUFF IS USELESS-----$/,$d' file

In a range expression like you have used, ',$' will specify "to the end of the file"

1 is first line in file, 
$ is last line in file.

output

Files:
 somefiles.tar.gz 1 2 3
 somefiles.tar.gz 1 2 3

With GNU sed, you can do

sed '/^-----THIS STUFF IS USELESS-----$/Q' file

where Q is similar to q quit command, but doesn't print the matching line

Answer 3

Dirty utility knife grep version:

cat your_output.txt | grep -B 99999999 "THIS STUFF IS USELESS" | grep -v "THIS STUFF IS USELESS"

Answer 4

Instead of trying to figure out how to express what what you don't want, just print what you DO want:

awk -v RS= '/Files:/' file

EDIT: Given your modified input:

awk '/^Files:$/{f=1} f; /^$/{f=0}' file

or:

awk '/^Files:$/{f=1} f; /^-----THIS STUFF IS USELESS-----$/{f=0}' file

if you prefer.

You can also use either of these:

awk '/^Files:$/,/^-----THIS STUFF IS USELESS-----$/' file
sed '/^Files:$/,/^-----THIS STUFF IS USELESS-----$/' file

but they are hard to extend later.

Answer 5

sed -e '/^-----THIS STUFF IS USELESS-----$/,$ d'