Let\'s say I have a signal change connected to a slot notify. If the change signal is emitted, the notify slot will start executing.
Now what happ
It depends on connection type you specified via calling connect
function. The only way when slot will be launched concurrently is if you specified Qt::DirectConnection
AND emitting signal in thread different from slot's thread. If you omit connection type, it would be Qt::AutoConnection
. In this case if you emit a signal from one thread, and catching it in another one (e.g. in main GUI thread) - Qt will put a slot's call to the message queue and will make all calls sequentially. Read this for further info - http://qt-project.org/doc/qt-4.8/threads-qobject.html#signals-and-slots-across-threads