When plotting with Bokeh, how do you automatically cycle through a color pallette?

Question

I want to use a loop to load and/or modify data and plot the result within the loop using Bokeh (I am familiar with Matplotlib\'s axes.color_cycle). Here is a simple exampl

Answer 1

Two small changes will make prior answer work for Python 3.

• changed: for m, color in zip(range(10), colors):

• prior: for m, color in itertools.izip(xrange(10), colors):

Answer 2

In Python > 3.7 you could do something like this:

from bokeh.palettes import Category10_10
       
color = Category10_10.__iter__()

p.line(x, y1, line_width=2, color=next(color))

This will cycle through each element of the list until exhausted each time you use next().

Every sequence type in python can return an iterator object.

Answer 3

You can define a simple generator that cycles colors for you.

In python 3:

from bokeh.palettes import Category10
import itertools

def color_gen():
    yield from itertools.cycle(Category10[10])
color = color_gen()

or in python 2 (or 3):

from bokeh.palettes import Category10
import itertools

def color_gen():
    for c in itertools.cycle(Category10[10]):
        yield c
color = color_gen()

and when you need a new color, do:

p.line(x, y1, line_width=2, color=color)
p.line(x, y2, line_width=2, color=color)

Here is the above example:

p = figure(width=400, height=400)
x = np.linspace(0, 10)

for m, c in zip(range(10), color):
    y = m * x
    p.line(x, y, legend='m = {}'.format(m), color=c)

p.legend.location='top_left'
show(p)

Answer 4

It is probably easiest to just get the list of colors and cycle it yourself using itertools:

import numpy as np
from bokeh.plotting import figure, output_file, show

# select a palette
from bokeh.palettes import Dark2_5 as palette
# itertools handles the cycling
import itertools  

output_file('bokeh_cycle_colors.html')

p = figure(width=400, height=400)
x = np.linspace(0, 10)

# create a color iterator
colors = itertools.cycle(palette)    

for m, color in zip(range(10), colors):
    y = m * x
    p.line(x, y, legend='m = {}'.format(m), color=color)

p.legend.location='top_left'
show(p)