I\'m running a Python script through a child process in Node.js, like this:
require(\'child_process\').exec(\'python celulas.py\', function (error, stdout, s
NodeJS supports doing this synchronously. Use this:
const exec = require("child_process").execSync;
var result = exec("python celulas.py");
// convert and show the output.
console.log(result.toString("utf8");
Remember to convert the buffer into a string. Otherwise you'll just be left with hex code.
You should use exec-sync
That allow your script to wait that you exec is done
really easy to use:
var execSync = require('exec-sync');
var user = execSync('python celulas.py');
Take a look at: https://www.npmjs.org/package/exec-sync
You need to remove the listeners exec installs to add to the buffered stdout and stderr, even if you pass no callback it still buffers the output. Node will still exit the child process in the buffer is exceeded in this case.
var child = require('child_process').exec('python celulas.py');
child.stdout.removeAllListeners("data");
child.stderr.removeAllListeners("data");
child.stdout.pipe(process.stdout);
child.stderr.pipe(process.stderr);
Use exit
event for the child process.
var child = require('child_process').exec('python celulas.py')
child.stdout.pipe(process.stdout)
child.on('exit', function() {
process.exit()
})
PS: It's not really a duplicate, since you don't want to use sync code unless you really really need it.
In my opinion, the best way to handle this is by implementing an event emitter. When the first spawn finishes, emit an event that indicates that it is complete.
const { spawn } = require('child_process');
const events = require('events');
const myEmitter = new events.EventEmitter();
firstSpawn = spawn('echo', ['hello']);
firstSpawn.on('exit'), (exitCode) => {
if (parseInt(code) !== 0) {
//Handle non-zero exit
}
myEmitter.emit('firstSpawn-finished');
}
myEmitter.on('firstSpawn-finished', () => {
secondSpawn = spawn('echo', ['BYE!'])
})