Jquery onclick on div

Question

I have a simple question. The following code works for all the tags:

$(\'*\').click(function(e) {  
    alert(1);
});

But, when I try this

Answer 1

Make sure it's within a document ready tagAlternatively, try using .live

$(document).ready(function(){

    $('#content').live('click', function(e) {  
        alert(1);
    });
});

Example:

$(document).ready(function() {
    $('#content').click(function(e) {  
      alert(1);
    });
});

#content {
    padding: 20px;
    background: blue;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<div id="content">Hello world</div>

As of jQuery 1.7, the .live() method is deprecated. Use .on() to attach event handlers.

$('#content').on( "click", function() {
    alert(1);
});

Answer 2

js

<script
  src="https://code.jquery.com/jquery-2.2.4.min.js"
  integrity="sha256-BbhdlvQf/xTY9gja0Dq3HiwQF8LaCRTXxZKRutelT44="
  crossorigin="anonymous"></script>


<script type="text/javascript">

$(document).ready(function(){
    $("#div1").on('click', function(){
            console.log("click!!!");
        });
});

</script>

html

<div id="div1">div!</div>

Answer 3

May the div with id="content" not be created when this event is attached? You can try live() jquery method.

Else there may be multiple divs with the same id or you just spelled it wrong, it happens...

Answer 4

Nothing.

$('#content').click(function(e) {  
    alert(1);
});

Will bind to an existing HTML element with the ID set to content, and will show a message box on click.

• Make sure that #content exists before using that code
• That the ID is unique
• Check your Javascript console for any errors or issues

Answer 5

Wrap the code in $(document).ready() method or $().

$(function(){

$('#content').click(function(e) {  
    alert(1);
});

});

Answer 6

Check out this fiddle ... you're doing it correctly. Make sure the id is content and also check to see there are no other elements with the same id. If there are multiple elements with the same id, it will bind to the first one. That might be why you arn't seeing it.