How to display only files from aws s3 ls command?

Question

I am using the aws cli to list the files in an s3 bucket using the following command (documentation):

aws s3 ls s3://mybucket --recursive --human-readable --         


        

Answer 1

My Solution

List only files recursively using aws cli.

aws s3 ls s3://myBucket --recursive | awk 'NF>1{print $4}' | grep .

grep . - Clear empty lines.

---

Example: aws s3 ls s3://myBucket

                           PRE f5c10c1678e8484482964b8fdcfe43ad/
                           PRE f65b94ad31734135a61a7fb932f7054d/
                           PRE f79b12a226b542dbb373c502bf125ffb/
                           PRE logos/
                           PRE test/
                           PRE userpics/
2019-05-14 10:56:28       7754 stage.js

Solution: aws s3 ls s3://myBucket --recursive | awk 'NF>1{print $4}' | grep .

stage.js

Answer 2

Use the s3api with jq (AWS docu aws s3api list-objects):

This mode is always recursive.

$ aws s3api list-objects --bucket "bucket" | jq -r '.Contents[].Key'
a.txt
foo.zip
foo/bar/.baz/a
[...]

You can filter sub directories by adding a prefix (here foo directory). The prefix must not start with an /.

$ aws s3api list-objects --bucket "bucket" --prefix "foo/" | jq -r '.Contents[].Key'
foo/bar/.baz/a
foo/bar/.baz/b
foo/bar/.baz/c
[...]

jq Options:

• -r = Raw Mode, no quotes in output
• .Contents[] = Get Contents Object Array Content
• .Key = Get every Key Field (does not produce a valid JSON Array, but we are in raw mode, so we don't care)

Addendum:

You can use pure AWS CLI, but the values will be seperated by \x09 = Horizontal Tab (AWS: Controlling Command Output from the AWS CLI - Text Output Format)

$ aws s3api list-objects --bucket "bucket" --prefix "foo/" --query "Contents[].Key" --output text
foo/bar/.baz/a   foo/bar/.baz/b   foo/bar/.baz/c   [...]

AWS CLI Options:

• --query "Contents[].Key" = Query Contents Object Array and get every Key inside
• --output text = Output as Tab delimited Text with now Quotes

Addendum based on Guangyang Li Comment:

Pure AWS CLI with New Line:

$ aws s3api list-objects --bucket "bucket" --prefix "foo/" --query "Contents[].{Key: Key}" --output text
foo/bar/.baz/a
foo/bar/.baz/b
foo/bar/.baz/c
[...]

Answer 3

Simple command would be

aws s3 ls s3://mybucket --recursive --human-readable --summarize |cut -d ' ' -f 8

If you need the timestamp, just update command field values.