how to ignore blank lines and comment lines using awk

Question

i am writing this code:

awk -F\'=\' \'!/^$/{arr[$1]=$2}END{for (x in arr) {print x\"=\"arr[x]}}\' 1.txt 2.txt

this code ignore blank lines,

Answer 1

awk 'NF && !/^[:space:]*#/' data.txt

Because '[:space:]*' catches none or more spaces.

Answer 2

awk 'NF && $1!~/^#/' data.txt

Will print all non-blank lines (number of fields NF is not zero) and lines that don't contain # as the first field.

It will handle a line of whitespace correctly since NF will be zero, and leading blanks since $1 will ignore them.

Answer 3

Change !/^$/ to

!/^($|#)/

or

!/^($|[:space:]*#)/

if you want to disregard whitespace before the #.