iOS — get pointer from NSString containing address

Question

If I have a pointer to an object foo with address (say) 0x809b5c0, I can turn that into an NSString by calling

NSString* fooString = [NSString stringWithForm         


        

Answer 1

Convert it to an integer, then cast it to whatever type it's supposed to be...

NSUInteger myInt = [ myStr integerValue ];
char * ptr       = ( char * )myInt;

That said, I really don't understand why you will need this...

Answer 2

In its completeness...

To address-string

NSString *foo = @"foo";
NSString *address = [NSString stringWithFormat:@"%p", foo];

And back

NSString *fooAgain;
sscanf([address cStringUsingEncoding:NSUTF8StringEncoding], "%p", &fooAgain);

Answer 3

This snippet worked for me:

NSString *pointerString = @"0x809b5c0";
NSObject *object;
sscanf([pointerString cStringUsingEncoding:NSUTF8StringEncoding], "%p", &object);

Answer 4

Use an NSMapTable instead:

MyClass* p = [[MyClass alloc]init];
NSMapTable* map = [NSMapTable mapTableWithKeyOptions:NSMapTableStrongMemory valueOptions:NSMapTableStrongMemory];
[map setObject:whateverValue forKey:p];
// ...
for(MyClass* key in map) {
// ...
}

Answer 5

In my experience its easier to convert the pointer's address to an NSInteger, like this:

MyObject *object=[[MyObject alloc]init];
//...
NSInteger adress=(NSInteger)object;

Now reverse:

MyObject *otherObject=(MyObject*)adress;

Now: object==otherObject