Java - always keep two decimal places even in zeroes

Question

I am trying to keep two decimal places, even if then numbers are zeroes, using DecimalFormatter:

DecimalFormat df = new DecimalFormat(\"#.00\");         


        

Answer 1

m_interest = Double.valueOf(String.format("%.2f", sum));

Answer 2

Use BigDecimal instead, which supports the formatting approach you seek.

This question details it: How to print formatted BigDecimal values?

Answer 3

It is because you are using Double.valueOf on the DecimalFormat and it is converting the formatted number back to a double, therefore eliminating the trailing 0s.

To fix this, only use the DecimalFormat when you are displaying the value.

If you need m_interest calculations, keep it as a regular double.

Then when displaying, use:

System.out.print(df.format(m_interest));

Example:

DecimalFormat df = new DecimalFormat("#.00");
double m_interest = 1000;
System.out.print(df.format(m_interest)); // prints 1000.00

Answer 4

DecimalFormat and NumberFormat should work just fine. A currency instance could work even better:

import java.text.DecimalFormat;
import java.text.NumberFormat;

public class Foo {
   public static void main(String[] args) {
      DecimalFormat df = new DecimalFormat("#0.00");

      NumberFormat nf = NumberFormat.getInstance();
      nf.setMinimumFractionDigits(2);
      nf.setMaximumFractionDigits(2);

      NumberFormat cf = NumberFormat.getCurrencyInstance();

      System.out.printf("0 with df is: %s%n", df.format(0));
      System.out.printf("0 with nf is: %s%n", nf.format(0));
      System.out.printf("0 with cf is: %s%n", cf.format(0));
      System.out.println();
      System.out.printf("12345678.3843 with df is: %s%n",
            df.format(12345678.3843));
      System.out.printf("12345678.3843 with nf is: %s%n",
            nf.format(12345678.3843));
      System.out.printf("12345678.3843 with cf is: %s%n",
            cf.format(12345678.3843));
   }
}

This would output:

0 with df is: 0.00
0 with nf is: 0.00
0 with cf is: $0.00

12345678.3843 with df is: 12345678.38
12345678.3843 with nf is: 12,345,678.38
12345678.3843 with cf is: $12,345,678.38

Answer 5

Why don't you simply Math.round(value * 100) / 100.0 ?