Regex: how to know that string contains at least 2 upper case letters?

Question

How to know that string contains at least 2 upper case letters? For example these are valid strings \"Lazy Cat\", \"NOt very lazy cat\". Working with Java 1.7.

Answer 1

This regex works.

string.matches(".*[A-Z].*[A-Z].*")

Answer 2

Try this:

string.matches("[A-Z]+.*[A-Z]+");

Answer 3

You have somany regex answers right now,

Go for it if you don't want to use **regex**,

String someString = "abcDS";
int upperCount = 0;
for (char c : someString.toCharArray()) {
    if (Character.isUpperCase(c)) {
        upperFound++;
    }
}
// upperFound  here weather >2 or not

Answer 4

I'll now show you a full solution, I'll guide you.

If you don't want to use regex, you can simply loop on the String, chat by char and check whether it's an upper case:

for (int i=0;i<myStr.length();i++)
{
     //as @sanbhat suggested, use Character#isUpperCase on each character..
}

Answer 5

Try with following regex:

"^(.*?[A-Z]){2,}.*$"

or

"^(.*?[A-Z]){2,}"