How to get il of one method body with roslyn?

Question

I want to get il of one method in my c# source code file.I have opened solution with roslyn and find the method symbol like below

Roslyn.Compilers.Common.         


        

Answer 1

Unfortunately, the IL generation is entirely hidden inside the Emit call in Roslyn. But I'll give a simple to get you started.

Let's suppose you start of with an existing compilation:

var initial = CSharpCompilation.Create("Existing")
    .AddReferences(MetadataReference.CreateFromFile(typeof(object).Assembly.Location))
    .AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(@"    
        namespace Test
        {
            public class Program
            {
                public static void HelloWorld()
                {
                    System.Console.WriteLine(""Hello World"");
                }
            }
        }"));    
var method = initial.GetSymbolsWithName(x => x == "HelloWorld").Single();

where method is your ISymbol. Then you can do following:

// 1. get source
var methodRef = method.DeclaringSyntaxReferences.Single();
var methodSource =  methodRef.SyntaxTree.GetText().GetSubText(methodRef.Span).ToString();

// 2. compile in-memory as script
var compilation = CSharpCompilation.CreateScriptCompilation("Temp")
    .AddReferences(initial.References)
    .AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(methodSource, CSharpParseOptions.Default.WithKind(SourceCodeKind.Script)));

using (var dll = new MemoryStream())
using (var pdb = new MemoryStream())
{
    compilation.Emit(dll, pdb);

    // 3. load compiled assembly
    var assembly = Assembly.Load(dll.ToArray(), pdb.ToArray());
    var methodBase = assembly.GetType("Script").GetMethod(method.Name, new Type[0]);

    // 4. get il or even execute
    var il = methodBase.GetMethodBody();
    methodBase.Invoke(null, null);
}

In a more complex case, you'd probably need to emit the entire/initial compilation, and get the generated method via reflection.

Refer to this post to find out what you can do with the results of GetMethodBody().