bash scripting - read single keystroke including special keys enter and space

Question

Not sure if I should put this on stackoverflow or unix.stackexchange but I found some similar questions here, so here it goes.

I\'m trying to create a script to be c

Answer 1

#!/bin/bash
SELECT=""
# prevent parsing of the input line
IFS=''
while [[ "$SELECT" != $'\x0a' && "$SELECT" != $'\x20' ]]; do
  echo "Select session type:"
  echo "Press <Enter> to do foo"
  echo "Press <Space> to do bar"
  read -s -N 1 SELECT
  echo "Debug/$SELECT/${#SELECT}"
  [[ "$SELECT" == $'\x0a' ]] && echo "enter" # do foo
  [[ "$SELECT" == $'\x20' ]] && echo "space" # do bar
done

Answer 2

Try setting the read delimiter to an empty string then check the builtin $REPLY variable:

read -d'' -s -n1

For some reason I couldn't get it to work specifying a variable.

Answer 3

There are a couple of things about read that are relevant here:

• It reads a single line
• The line is split into fields as with word splitting

Since you're reading one character, it implies that entering Enter would result into an empty variable.

Moreover, by default rules for word splitting, entering Space would also result into an empty variable. The good news is that you could handle this part by setting IFS.

Change your read statement to:

IFS= read -s -n 1 SELECT

and expect a null string instead of $'\x0a' when entering Enter.