Insert for every 5 elements using Javascript

Question

I have a simple list of images that is being controlled via a CMS (ExpressionEngine). Like this:

    

        

                      

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Answer 1

You can just create a div for every fith element and move the links into them using the append method:

var wrapper = $('.wrapper');
var div;
$('a', wrapper).each(function(i,e){
    if (i % 5 == 0) div = $('<div/>').addClass('slide').appendTo(wrapper);
    div.append(e);
});

Demo: http://jsfiddle.net/Guffa/ybrxu/

Answer 2

You need to use jQuery slice with wrap

Check this question

Answer 3

Here's one way:

Example: http://jsfiddle.net/T6tu4/

$('div.wrapper > a').each(function(i) {
    if( i % 5 == 0 ) {
        $(this).nextAll().andSelf().slice(0,5).wrapAll('<div class="slide"></div>');
    }
});

Here's another way:

Example: http://jsfiddle.net/T6tu4/1/

var a = $('div.wrapper > a');

for( var i = 0; i < a.length; i+=5 ) {
    a.slice(i, i+5).wrapAll('<div class="slide"></div>');
}

Answer 4

Try this:

$(function(){
    var curDiv = null;
    var mainDiv = $("div.wrapper");
    $("span", mainDiv).each(function(i, b){
        if(i%5 == 0) {
            curDiv = $("<div class='slide'/>").appendTo(mainDiv);
        }
        curDiv.append(b);
    });
});

Answer 5

Use slice() to select the element subset then wrapAll() to wrap the div around them. Here's a function that does that.

var wrapEveryN = function(n, elements, wrapper) {
   for (var i=0; i< elements.length; i+=n) {
       elements.slice(i,i+n).wrapAll(wrapper);
   }
}

wrapEveryN( 5, $(".wrapper a"), '<div class="slide"></div>' );

Demo: http://jsfiddle.net/C5cHC/

Note that the second parameter of slice may go out of bounds, but jQuery seems to handle this automatically.

Answer 6

I think this would do that:

var links = $('.wrapper').children();
for (var i = 0, len = links.length; i < len; i += 5) {
    links.slice(i, i + 5).wrapAll('<div class="slide"/>');
}